A ship moves along the equator to the east with a speed 30 km/h. Southeastern wind blows 60 o to the east with 15 kmh -1 . Find the wind velocity relative to the ship.
Text Solution
Verified by ExpertsThe correct answer is:
A
v ws = v w – v s
= (15 cos 60 
+ 15 sin 60 
) – 30 
|v|= 
= 39.7 kmh -1
tan β β = 7.5/37.8 = 1/5
β β = tan -1 1/5 North of West.
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